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Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to

Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to

Options

(a) 1/R
(b) 1/√R
(c) R
(d) 1/R³/²

Correct Answer:

1/R

Explanation:

Kinetic energy of the satellite=1/2mv₀²
v₀=√GM/R
Now, Putting the value of v₀, We get,
Kinetic energy=1/2m(√GM/R)²
=1/2 GMm/R
Therefore, Kinetic energy is proportional to 1/R.

BHU2003
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