In Young’s experiment, the ratio of maximum to minimum intensities of the fringe

In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4:1. The amplitudes of the coherent sources are in the ratio

Options

(a) (4:1)
(b) (3:1)
(c) (2:1)
(d) (1:1)

Correct Answer:

(3:1)

Explanation:

I(max) / I(min) = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²

⇒ 4 / 1 = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²

⇒ (ɑ₁ + ɑ₂) / (ɑ₁ – ɑ₂) = 2 / 1

⇒ ɑ₁ + ɑ₂ = 2 (ɑ₁ – ɑ₂)

⇒ 3ɑ₂ = ɑ₁

⇒ ɑ₁ / ɑ₂ = 3 / 1 = 3 : 1

admin:

Related Questions

  1. The work of 146 kJ is performed in order to compress one kilo mole fo gas adiabatically
  2. At which place, Earth’s magnetism becomes horizontal
  3. The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
  4. A polished metal plate has a rough and black-spot. It is heated to 1400 K
  5. Two similar springs P and Q have spring constants Kp and Kq, such that Kp>Kq.