In vacuum, to travel distance d, light takes time t and in medium to travel distance

In vacuum, to travel distance d, light takes time t and in medium to travel distance 5d, it takes time T. The critical angle of the medium is

Options

(a) sin⁻¹(5T/t)
(b) sin⁻¹(5t/3T)
(c) sin⁻¹(5t/T)
(d) sin⁻¹(3t/5T)

Correct Answer:

sin⁻¹(5t/T)

Explanation:

In vacuum, c = d / t

In medium, v = 5d / T

As refractive index , μ = c / v = (d/t) / (5d/T) = T / 5t

Also, sin C = 1 / μ [If C is critical angle]

Therefore, C = sin⁻¹ [5t / T]

admin:

Related Questions

  1. One coolie takes 1 minute to raise a suitcase through a height of 2 m
  2. The wavelength λₑ of an electron and λₚ of a photon are of same energy E are related by
  3. The r.m.s speed of the molecules of a gas in a vessel is 400 m/s
  4. Characteristic X-rays are produced due to
  5. A battery charges a parallel plate capacitor seperated by distance(d) so that the energy