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In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,

In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω, then the value of power factor of the circuit is

Options

(a) (4/3)
(b) (3/4)
(c) zero
(d) infinity

Correct Answer:

(4/3)

Explanation:

Power factor cos ɸ = Resistance / Impedance = 4 / 3.

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