In the electrolysis of water, one faraday of electrical energy would evolve

Options

(a) one mole of oxygen
(b) one g atom of oxygen
(c) 8 g of oxygen
(d) 22.4 litres of oxygen

Correct Answer:

8 g of oxygen

Explanation:

Hydrolysis of water can be represented by the following equations: 2H₂O ⇌ O₂ + 4H⁺ + 4e⁻. 4 Faraday of charge liberate O₂ = 32 g. Therefore 1 Faraday of charge liberate O₂ = 32/4 = 8g.