In an isobaric process,when temperature changes from T₁ to T₂, ΔS is equal to
Options
(a) 2.303 Cp log (T₂/T₁)
(b) 2.303 Cp ln(T₂/T₁)
(c) Cp ln (T₁/T₂)
(d) Cv ln (T₂/T₁)
Correct Answer:
2.303 Cp log (T₂/T₁)
Explanation:
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