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In a parallel plate capacitor with plate area A and charge Q, the force on one plate

In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to

Options

(a) Q²/ε₀A²
(b) Q²/2ε₀A²
(c) Q²/ε₀A
(d) Q²/2ε₀A

Correct Answer:

Q²/2ε₀A

Explanation:

Force between the plates of a parallel plate capacitor |F| = V²A / 2ε₀ = Q² / 2ε₀A

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