If the density of earth is doubled keeping its radius constant then acceleration

If the density of earth is doubled keeping its radius constant then acceleration due to gravity will be (g=9.8 m/s²)

Options

(a) 19.6 m/s²
(b) 9.8 m/s²
(c) 4.9 m/s²
(d) 2.45 m/s²

Correct Answer:

19.6 m/s²

Explanation:

Acceleration due to gravity g=GM/R² ——-(1)
The radius is constant, volume also constant.
If volume is constant, density is proportional to mass.(v=m/ρ)
The density is doubled, the mass is also doubled. (M’=2M)
The new acceleration due to gravity g’=GM’/R’²
Put the value M’=2M and R’=R
g’=G(2M)/R²
g’=2GM/R² ——–(2)
Substituting equations (1) and (2), we get
g’=2g
g=9.8 m/s²
g’=2×9.8=19.6 m/s²

admin:

Related Questions

  1. If a solid sphere of mass 1 kg and radius 0.1 m rolls without slipping at a uniform
  2. A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
  3. Photoelectric emision occurs only when the incident light has more than a certain minimum
  4. A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
  5. what should be the velocity of an electron so that its momentum becomes equal