If the density of earth is doubled keeping its radius constant then acceleration

If the density of earth is doubled keeping its radius constant then acceleration due to gravity will be (g=9.8 m/s²)

Options

(a) 19.6 m/s²
(b) 9.8 m/s²
(c) 4.9 m/s²
(d) 2.45 m/s²

Correct Answer:

19.6 m/s²

Explanation:

Acceleration due to gravity g=GM/R² ——-(1)
The radius is constant, volume also constant.
If volume is constant, density is proportional to mass.(v=m/ρ)
The density is doubled, the mass is also doubled. (M’=2M)
The new acceleration due to gravity g’=GM’/R’²
Put the value M’=2M and R’=R
g’=G(2M)/R²
g’=2GM/R² ——–(2)
Substituting equations (1) and (2), we get
g’=2g
g=9.8 m/s²
g’=2×9.8=19.6 m/s²

admin:

Related Questions

  1. An elevator car whose floor to ceiling distance is equal to 2.7m starts
  2. A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10⁻⁵ Wb.
  3. An LCR circuit contains resistance of 100 ohm and a supply of 200 volt at 300 radian
  4. A circular disc X of radius R is made from an iron plate of thickness t and another disc
  5. In an L-C-R series resonant circuit, the capacitance is changed from C to 4C.