If the density of earth is doubled keeping its radius constant then acceleration

If the density of earth is doubled keeping its radius constant then acceleration due to gravity will be (g=9.8 m/s²)

Options

(a) 19.6 m/s²
(b) 9.8 m/s²
(c) 4.9 m/s²
(d) 2.45 m/s²

Correct Answer:

19.6 m/s²

Explanation:

Acceleration due to gravity g=GM/R² ——-(1)
The radius is constant, volume also constant.
If volume is constant, density is proportional to mass.(v=m/ρ)
The density is doubled, the mass is also doubled. (M’=2M)
The new acceleration due to gravity g’=GM’/R’²
Put the value M’=2M and R’=R
g’=G(2M)/R²
g’=2GM/R² ——–(2)
Substituting equations (1) and (2), we get
g’=2g
g=9.8 m/s²
g’=2×9.8=19.6 m/s²

admin:

Related Questions

  1. The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
  2. A potentiometer wire of length L and a resistance r are connected in series with
  3. Assertion(A) :The change in kinetic energy of a particle is equal to the work done
  4. A person of mass 60 kg is inside a lift of mass 940 kg and presses the button on control panel.The lift starts moving upwards wi
  5. Two positive ions, each carrying a charge q, are separated by a distance d