If n = 6, the correct sequence for filling of electrons will be:
Options
(a) ns→(n–2)f→(n–1)d→np
(b) ns→(n–1)d→(n–2)f→np
(c) ns→(n–2)f→np→(n–1)d
(d) ns→np(n–1)d→(n–2)f
Correct Answer:
ns→(n–2)f→(n–1)d→np
Explanation:
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