If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle makes angle of 45⁰ with the horizontal. The real dip is
Options
(a) tan⁻¹(√3/2)
(b) tan⁻¹(√3)
(c) tan⁻¹(3/√2)
(d) tan⁻¹(2/√3)
Correct Answer:
tan⁻¹(2/√3)
Explanation:
tan δ’ = tan δ / cos θ = tan 45° / cos 30°
tan δ’ = 1 / (√3/2) = 2 / √3
δ’ = tan⁻¹ (2 / √3)