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If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle

If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle makes angle of 45⁰ with the horizontal. The real dip is

Options

(a) tan⁻¹(√3/2)
(b) tan⁻¹(√3)
(c) tan⁻¹(3/√2)
(d) tan⁻¹(2/√3)

Correct Answer:

tan⁻¹(2/√3)

Explanation:

tan δ’ = tan δ / cos θ = tan 45° / cos 30°

tan δ’ = 1 / (√3/2) = 2 / √3

δ’ = tan⁻¹ (2 / √3)

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