If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is

If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is

(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032

0.0164

Here μᵥ=1.5230and μʀ=1.5145

Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187

Now, dispersive power, ω is given by,

ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164

UP2015

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