If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is

If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is

Options

(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032

Correct Answer:

0.0164

Explanation:

Here μᵥ=1.5230and μʀ=1.5145

Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187

Now, dispersive power, ω is given by,

ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164

admin:

Related Questions

  1. A satellite is launched into a circular orbit of radius R around earth while
  2. The wavelength of Kα line in copper is 1.5Å. The ionisation energy of K electron in copper is
  3. Two circuits have a mutual inductance of 0.1 H. What average e.m.f. is induced
  4. The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
  5. The molar specific heat at constant pressure of an ideal gas is (7/2)R. The ratio