If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is

If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is

Options

(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032

Correct Answer:

0.0164

Explanation:

Here μᵥ=1.5230and μʀ=1.5145

Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187

Now, dispersive power, ω is given by,

ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164

admin:

Related Questions

  1. Wave nature of light is verified by
  2. Two identical circular coils A and B are kept on a horizontal tube
  3. P-type semiconductors are made by adding impurity element
  4. The alternating current in a circuit is given by I=50 sin314t. The peak value
  5. Certain quantity of water cools from 70⁰ C to 60⁰C in the first 5 minutes and to 54⁰C