![](data:image/svg+xml;charset=utf-8,<svg height="300px" width="600px" xmlns="http://www.w3.org/2000/svg" version="1.1"/>)
I₄O₉ is a/an
Options
(a) Ionic compound
(b) Covalent compound
(c) Coordinate compound
(d) double salt
Correct Answer:
ionic compound
Explanation:
I₄O₉ is actually I(IO₃)₃. It is an ionic compound.
I(IO₃)₃ ⇌ I³⁺ + 3IO₃⁻
I₄O₉ is a/an
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