Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å

Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å. Number of spectral lines in the resulting spectrum emitted will be

Options

(a) 3
(b) 2
(c) 6
(d) 10

Correct Answer:

6

Explanation:

For the λ=975 Å
1 / λ = R [(1/n₁²) – (1/n₂²)]
where R is the Rydberg constant
Solving we get n₂ = n = 4 (Since, n₁ = 1 ground state)
Therefore number of spectral lines = n(n – 1) / 2 = 4(4 – 1) / 2 = 6.

admin:

Related Questions

  1. 1 a.m.u. is equivalent to
  2. In the Young’s double slit experiment, the intensity of light at a point on the screen
  3. An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
  4. An electric dipole of moment p is lying along a uniform electric field E. The work
  5. SI unit of permittivity is