Considering entropy (S) as a thermodynamic parameter, the criterion

Considering entropy (S) as a thermodynamic parameter, the criterion for the spontaneity of any process is

Options

(a) ΔS system + ΔS surroundings > 0
(b) ΔS system – ΔS surroundings > 0
(c) ΔS system > 0 only
(d) ΔS surroundings > 0 only

Correct Answer:

ΔS system + ΔS surroundings > 0

Explanation:

ΔS = Rln V₂/V₁,
Here the volume of gas increases from V₁ to V₂ at consant temperature T. The total increase in entropy of the system and its surroundings during the spontaneous process of expansion considered above is, thus R ln (V₂/V₁).Since V₂ > V₁, it is obvious that the spontaneous (irreversible) isothermal expansion of a gas is accompanied by a increase in the entropy of the system and its surroundings considered together.
ΔS(sys) + ΔS(surr > 0.

admin:

Related Questions

  1. The constituent of light oil is
  2. In a zero-order reaction.for every 10°C rise of temperature ,the rate is doubled.
  3. 5 g of hydrogen peroxide is present in 56 mL of solution. The solution
  4. In the periodic table going down in fluorine group
  5. An increase in pressure would favour which of the following reaction?