At S.T.P the density of CCl₄ vapours in g/L will be nearest to

Options

(a) 6.87
(b) 3.42
(c) 10.26
(d) 4.57

Correct Answer:

6.87

Explanation:

Molecular Weight of CCl₄ = 35.5 + 12 x 4 = 154
1 mole CCl₄ vapour=154 g
According to Avogadro’s hypothesis we know that the molar volume of a gas at STP is 22.4 litres
= 154/22.4 = 6.87