A parallel plate capacitor of a capacitance 1 pF has seperation between the plates

A parallel plate capacitor of a capacitance 1 pF has seperation between the plates is d. When the distance of seperation becomes 2d and wax of dielectric constant x is inserted in it the capacitance becomes 2 pF. What is the value of x?

Options

(a) 2
(b) 4
(c) 6
(d) 8

Correct Answer:

4

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

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  • Bhaiya dekho salon ne dala nahi tha explanation hum likh rahe hain.

    Before C =1pF
    After when d is doubled and dilectric is inserted
    C=2pF
    So x-
    Since C=(ε0.A/d)k after intertion of dielectric
    2=(ε0.A/2d)k (given)
    2=(C/2)k
    2=k/2. (Given)
    K=4

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