A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt battery. The energy stored in the coil is
Options
(a) 250 erg
(b) 250 J
(c) 125 erg
(d) 125 J
Correct Answer:
250 J
Explanation:
Energy U = (1/2) LI²
= (1/2) × 5 × (100/10)² = 250 J