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A circular disc rolls down an inclined plane. The ratio of rotational kinetic energy to total kinetic energy is
Options
(a) 1/2
(b) 1/3
(c) 2/3
(d) 3/4
Correct Answer:
1/3
Explanation:
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Kr=Iomega^2
=1÷2×1÷2MR^2×(V÷R)^2
r=1÷4MV^2-------(1)
Ke=1÷2MV^2
Kt=Kr+Ke
Kt=1÷4MV^2+1÷2MV^2
Kt=3÷4MV^2
Kr÷Kt=1÷3
=1:3