A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls

A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)

Options

(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C

Correct Answer:

3.3×10⁻¹⁸ C

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. The pair of quantities having same dimensions is
  2. The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
  3. Order of e/m ratio of proton, α-particle and electron is
  4. The distance of a geo-stationary satellite from the centre of the earth is nearest to
  5. The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²