A certain mass of gas occupies a volume of 300 c.c. at 27⁰C and 620 mm pressure.The volume of this gas at 47⁰C and 640 mm pressure will be

Options

(a) 400 c.c.
(b) 350 c.c.
(c) 310 c.c.
(d) 510 c.c.

Correct Answer:

310 c.c.

Explanation:

V₁ = 300 cc, V₂ = ?, P₁ = 620 mm , P₂ = 640 mm. T₁ = 27 + 273 = 300 K, T₂ = 47 + 273 = 320. From the relationship, P₁V₁ / T₁ = P₂V₂ / T₂. ⇒ V₂ = 620 * 300 * 320 / 300 * 640 = 310 c.c