8.2 L of an ideal gas weight 9.0 gm at 300 K and 1 atm pressure. The molecular mass of the gas is
Options
(a) 9
(b) 18
(c) 27
(d) 36
Correct Answer:
27
Explanation:
PV = nRT = (m / M) RT ⇒ M = mRT / PV = (9.0 × 0.0821 × 300) / (1 × 8.2) = 27
8.2 L of an ideal gas weight 9.0 gm at 300 K and 1 atm pressure. The molecular mass of the gas is
(a) 9
(b) 18
(c) 27
(d) 36
27
PV = nRT = (m / M) RT ⇒ M = mRT / PV = (9.0 × 0.0821 × 300) / (1 × 8.2) = 27