10g of hydrogen and 64g of oxygen were filled in a steel vessel and exploded.

10g of hydrogen and 64g of oxygen were filled in a steel vessel and exploded.Amount of water produced in this reaction will be

Options

(a) 3 moles
(b) 4 moles
(c) 1 moles
(d) 2 moles

Correct Answer:

4 moles

Explanation:

H₂(2g & 1mol) + 1/2 O₂(16g & 0.5mol) → H₂O(18g & 1mol)
10 g of H₂ = 5 mol
and 64 g of O₂ = 2mol
.·. In this reaction, oxygen is the limiting reagent so amount of H₂O produced depends on that of O₂.
Since of 0.5 mol of O₂ gives 1 mol H₂O
.·. 2 mol of O₂ will gives 4 mol H₂O.

admin:

Related Questions

  1. Among the following complexes the one which shows zero crystal field
  2. At equilibrium, the value of change in Gibb’s free energy (ΔG) is
  3. The volume of 0.05 M KMnO₄ solution required to oxidized completely 2.70g
  4. Standard enthalpy and standard entropy changes for the oxidation of ammonia
  5. The enthalpy of fusion of water is 1.435 kcal/mol.The molar entropy