1 c.c N₂O at NTP contains

1 c.c N₂O at NTP contains

Options

(a) (1.8/224) x 10²² atoms
(b) (6.02/22400) x 10²³ molecules
(c) (1.32/224) x 10²³ electrons
(d) all the above

Correct Answer:

all the above

Explanation:

At N.T.P 22400 cc of N₂O =6.02 x 10²³ molecules
1 cc contains = (6.02 x 10²³) / 22400 molecules

N₂O contains 3 atoms, so
= (3 x 6.02 x 10²³) / 22400 atoms
=1.8 / 224 x 10²² atoms

No of electrons in N₂O = (7*2)+8  =22

= (22 x 6.02 x 10²³) / 22400 electrons

=132.44 x 10²³ / 22400 electrons

=1.32 x 10²³ / 224 electrons

admin:

View Comments (2)

  • It is totally wrong answer ok.its answer is (b)part ok what are you doing.Can you explain why are you uploading the wrong answers.Please check the answer

    • kindly read the explanation. all options are correct answers as each option is in different units. so (d) is the correct answer.

Related Questions

  1. Which of the following statement about the member of any one homologous series
  2. Antiseptic chloroxylenol is
  3. Helium atom is two times heavier than a hydrogen molecule, the average kinetic energy
  4. The pair of species with the same bond order is:
  5. The correct order of stability of the superoxides is