ΔH°f (298 K) of methanol is given by the chemical equation

ΔH°f (298 K) of methanol is given by the chemical equation

(a) CH₄(g) + 1/2 O₂(g) → CH₃OH(g)
(b) C + 1/2 O₂(g) + 2H₂(g) → CH₃OH(l)
(c) C(diamond) + 1/2 O₂(g) + 2H₂(g) → CH₃OH(l)
(d) CO(g) + 2H₂(g) → CH₃OH(l)

C(diamond) + 1/2 O₂(g) + 2H₂(g) → CH₃OH(l)

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